1/(x+1)+x^2/(x^2-1)=1

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Solution for 1/(x+1)+x^2/(x^2-1)=1 equation: 



1/(x+1)+x^2/(x^2-1)=1

We move all terms to the left:

1/(x+1)+x^2/(x^2-1)-(1)=0



Domain of the equation: (x^2-1)!=0

We move all terms containing x to the left, all other terms to the right

x^2!=1

x^2!=1/

x^2!=√1/

x!=1

x∈R





Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R



We calculate fractions


(x^2*(x+1))/((x^2-1)*(x+1))+(1*(x^2-1))/((x^2-1)*(x+1))-1=0



We calculate terms in parentheses: +(x^2*(x+1))/((x^2-1)*(x+1)), so:

x^2*(x+1))/((x^2-1)*(x+1)

We multiply all the terms by the denominator


x^2*(x+1))

Back to the equation:

+(x^2*(x+1)))





We calculate terms in parentheses: +(1*(x^2-1))/((x^2-1)*(x+1)), so:

1*(x^2-1))/((x^2-1)*(x+1)

We multiply all the terms by the denominator


1*(x^2-1))

Back to the equation:

+(1*(x^2-1)))

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